Week 8: File I/O (streams)
CONTENTS:
- Readings
- Background
- PreQuiz Assignment (due Monday March 3 at 9am)
- Recitation
- Recitation Submission Guidelines
- Homework
Readings
Please note the advised readings of “Brief C++ Late Objects” - Cay Horstmann:
- Monday: Review chapter 6 as needed
- Wednesday: 8.1, 8.2
- Friday: 8.2
Background
File Input/Output
So far in class, we’ve been using the iostream standard library. This library has provided us with methods like cin and cout. cin is the method that reads from standard input (i.e. in the terminal via the keyboard) and cout is for writing to standard output.
In this background section we’ll cover file input, which will allow you to read information from a file and begin creating programs that can be turned off and on while maintaing knowledge of past times it was turned on. To do this, we’ll need to include C++’s fstream library, which is short for “file stream”.
Reading Lines From A File
Step 0. Include the library.
A lot of code is needed in secret to get this to work. Just like we have #include<iostream> to get cin and cout for us
//
#include<fstream>Step 1. Make a stream object.
Create an object (a variable) of file stream type. If you want to open a file for reading only, then the ifstream object should be used (short for “input file stream”).
// create an `i`nput `f`ile `stream` object
ifstream file_input;Step 2. Open a file.
Once you have a file stream object, you need to open the file. To do this, use the ifstream object’s open() method (function), which takes only one parameter: the file name as a string (surrounded by “ “ if the file name is given directly).
// open myTextFile.txt with the file stream object
file_input.open("myTextFile.txt");NOTE: this is a common source of bugs in coding with file streams. The myTextFile.txt file needs to exist in the same directory as the program that you are running. You can access other directories on the computer by learnign more about “file paths”. For now we will not cover it.
Step 3. Checking for open files.
It is always good practice to check if the file has been opened properly and take an appropriate action if not. To check if a file was successfully opened, you may use the fail() or is_open() methods.
fail(): This method will return a boolean value true if the file failed to open and false otherwise.
if (file_input.fail()) // true when file fails to open
{
cout << "Could not open file." << endl;
// return to terminate the program
// EXIT_FAILURE to indicate that the program didn't function as expected
return EXIT_FAILURE;
}
// do things with the fileis_open(): This method will return a boolean value true if the file has successfully opened and false otherwise.
if (file_input.is_open()) // true when file opens sucessfully
{
// do things with the file
}
else
{
cout << "Could not open file." << endl;
}Step 4. Read lines from the file.
To read a line from the file, you can use getline(file_input, line) which returns true as long as an additional line has been successfully assigned to the variable line. Once no more lines can be read in, getline returns false. So we can set up a while loop where the condition is the call to getline.
string line = "";
int line_idx = 0;
// get the next line from the file and store in 'line' variable
// continue looping as long as there is data to be processed in the file
while ( getline(file_input, line) )
{
// print each line read from the file
cout << line_idx << ": " << line << endl;
// increment index(count of lines in the file)
line_idx++;
}.eof(): This method will return a boolean value true if all the data in the file was processed and false otherwise.
string line = "";
int line_idx = 0;
// continue looping as long as there is data to be processed in the file
while (!file_input.eof())
{
// get the next line from the file and store in 'line' variable
getline(file_input, line);
// print each line read from the file
cout << line_idx << ": " << line << endl;
// increment index(count of lines in the file)
line_idx++;
}Step 5. Closing a file.
When you are finished processing your files, it is recommended to close all the opened files before the program is terminated. You can do this by using the .close() function on your file stream object.
// closing the file
file_input.close();Step 6. Putting it all together.
If we put all the previous steps together, this is the final piece of code we get.
#include<iostream>
#include<fstream>
using namespace std;
int main( )
{
// create an input file stream object
ifstream file_input;
// open myTextFile.txt with the file stream object
file_input.open( "myTextFile.txt" );
// check if file opened successfully
if ( file_input.fail() )
{
cout << "Could not open file." << endl;
return EXIT_FAILURE;
}
// since the if returns, we don't need an else...
// do things with the file
string line = "";
int line_idx = 0;
// read each line from the file
while ( !file_input.eof() )
{
// gets line of text from file_input, stores it in line
getline( file_input, line );
// print each line read from the file
cout << line_idx << ": " << line << endl;
// increment index (count of lines in the file)
line_idx++;
}
// closing the file
file_input.close( );
return 0;
}RECALL: the open() function requires a correct path to the file. If the myTextFile.txt isn’t there then we will see a print out: Could not open file.
PreQuiz Assignment (due Monday March 3 at 9am)
Recitation
Recitation Spot The Error- Problem 1
The program below intends to prints average of the scores. Identify the error(s) in the code below, and write the correct line(s).
#include <iostream>
#include <string>
using namespace std;
int main()
{
int size = 6;
double scores[size] = {85.4, 90.3, 100, 89, 74.5, 95.0, 82.3};
double sum = 0;
for(int i = 0; i < size; i++)
{
sum += scores[i];
}
int avg = sum / 6.0;
cout << "Average = " << avg << endl;
return 0;
}
Recitation Spot The Error- Problem 2
The program below displays transpose of a given matrix. The transpose of a matrix is simply a flipped version of the original matrix by switching its rows with its columns. Identify the error(s) in the code below, and write the correct line(s).
#include <iostream>
using namespace std;
// Function to calculate the transpose of a matrix
double transposeMatrix(int matrix[][3], int n, int m)
{
for (int i = 0; i < n; i++)
{
for (int j = i + 1; j < m; j++)
{
temp = matrix[i][j];
matrix[i][j] = matrix[j][i];
matrix[j][i] = temp;
}
}
return matrix;
}
int main()
{
const int rows = 3;
const int cols = 3;
int originalMatrix[rows][cols] =
{
{1, 1, 1},
{2, 2, 2},
{3, 3, 3}
};
// Calculate the transpose matrix using the function
int result[rows][cols] = transposeMatrix(originalMatrix[3][3], rows, cols);
// Display the transpose matrix
cout << "Transpose Matrix:" << endl;
for (int i = 0; i < rows; i++)
{
for (int j = 0; j < cols; j++)
{
cout << result[i][j] << " ";
}
cout << endl;
}
return 0;
}
Recitation Spot The Error- Problem 3
The program below tries to print all the items specified in the item array. Identify the error(s) in the code below, and write the correct line(s).
#include <iostream>
using namespace std;
int main()
{
int N = 3;
char item[] = {"book", "pen", "pencil", "eraser"};
//printing all the items
for (int i = 0; i < N; i++)
{
cout << "The item list has " << items[j] << endl;
}
return 0;
}
Recitation Spot The Error- Problem 4
The program below prints the strings that have length equal to 4. Identify the error(s) in the code below, and write the correct line(s).
#include <iostream>
#include <string>
using namespace std;
int main()
{
const int N = 6;
string animals[N] = {"lion", "cat", "bear", "dog", "elephant", "fox"};
for (int i = 0; i < N; i++)
{
if (animals.length()[i] == 4)
{
cout << animals[i] << endl;
}
}
return 0;
}
Recitation Matrix Sum - Problem 5
The sum of two matrices is found by adding together corresponding entries in each matrix, as shown above. (For example, the numbers at (row 1, column 1) of each matrix are added together to get the (row 1, column 1) number of the sum matrix.)
Write a function that accepts two 2x3 integer arrays as input parameters and displays the sum matrix (displayed in 2 rows). Example header:
void matrixSum(int a[2][3], int b[2][3])
Then, create a main() function that asks the user to input the values for each matrix one row at a time. Store these in two arrays, and pass them to matrixSum. Example output (red is user input)
Recitation Matrix Sum - Problem 5.a.: Algorithm
Write out the steps you would use to solve this problem by hand as pseudocode.
Recitation Matrix Sum - Problem 5.b.: Implementation
Translate your pseudocode into a C++ program to solve the above code, verify that your program works as expected.
Recitation Coding Telephone
For this activity, you will need to break into groups of approximately 6-8. The basic idea of the game is simple: We will give you some starting piece of code, with a short region of the code marked for “Coding Telephone”. The first person in your group will have to translate the code entirely to comments, leaving no actual code in that region behind. They will pass this comment file on to the second person in your group, who will translate the comments back into code. Then the next person will translate the code to comments, so on and so forth until everyone in your group has participated. Then you will attempt to compile your code and run it, and see what happens. Think of it like the game Telephone, but with code.
The only person who should view this starting code is the first person in your group. Make sure to keep the code secret at each stage so others cannot see it. You will each have five minutes to translate your code. During the time you are not coding, you are welcome to work on the other questions in this recitation assignment.
Once your group has completed the game, work together to answer the following questions:
Did your final code compile? If not, what error did it fail with? If this is an easy to fix error, fix it and move on to the next question.
If your code compiled, did it run? If not, what error did it fail with? If so, what did it print?
Compile and run the original code, and compare it with the code you ended with. How did it change? Where were some areas of miscommunication?
Submit your answers to these questions along with your final Telephone code for this problem on Canvas.
Recitation Submission Guidelines
Important: Follow these instructions carefully when preparing your recitation assignments. Your final submission should be in a single document, and the only action required on Canvas is uploading that document.
- Documentation:
- Create a pdf that includes your submission for all recitation questions. This is the pdf you will upload to your canvas assignment. Feel free to use Word/Google doc to create the pdf.
- Clearly label each question with its corresponding number and include content as applicable (see #2).
- Content to Include:
- Screenshots of Your Code:
- For each question, include a screenshot of your code.(corrected code in case of spot the errors)
- Screenshots of Code Output (if applicable):
- For some longer questions, it might be required to take a screenshot of the code’s output. Include these screenshots as part of your submission.
- Longer Recitation Questions (Multiple Parts):
- Option A:
- Comment your answers directly within your code file.(Spot the errors)
- Take screenshots of the commented code and paste them into your document.
- Option B:
- Take screenshots of the unmodified code.
- Write your answers (Free Response/Pseudocode/Edge case identifictation) to the subquestions in the pdf document next to the corresponding screenshots.
- Option A:
- Screenshots of Your Code:
- Submission:
- Upload the final pdf document to Canvas. This is the only action required on Canvas for your submission.
By following these steps, your submission will be clear, organized, and standardized across all recitation assignments.
Homework
Warning: You are not allowed to use global variables for this homework.
All function names, return types, and parameters must precisely match those shown. You may not use pass by reference or otherwise modify the function prototypes. You are welcome to create additional functions that may help streamline your code.
Most Popular Word
A word is said to be most popular if it occurs more frequently than any other word. Write a function named mostPopularWord() that finds the most popular word in an array and prints the word, its frequency, and the indices where it was found. You may assume there’s always one correct answer, and the array will be non-empty. If it has equal occurrence, then we always consider the most recent one.
Note: You do not need sorting to solve this.
void mostPopularWord(string words[], const int WORDS_SIZE)
{
// ...
}| Function: | mostPopularWord(string[], const int) |
| Purpose: | Print the word with the highest frequency, its count, and its index positions in the array. |
| Parameters: | string words: Array of words const int WORDS_SIZE: The size of word array |
| Return value: | - The function should print the word with the highest frequency, its count, and its index positions in the array. - The function doesn’t return any value to the main function. |
| Error Handling/ Boundary Conditions: | - If two or more words have the same frequency, the word that appears last will be considered the most popular; see Test code 2 below - You may assume the words[] array is always non-empty. |
Example:
// Assume the proper libraries are included
// Assume the proper implementation of mostPopularWord() is included
int main()
{
const int WORDS_SIZE = 4;
string words[WORDS_SIZE] = {"mail", "text", "spam", "spam"};
mostPopularWord(words, WORDS_SIZE);
return 0;
}
// OUTPUT
// The most popular word: spam
// Frequency: 2
// Found at pos: 2 3For Question 1, develop and validate your solution in VS Code. Once you are happy with your solution, go to coderunner on Canvas and paste mostPopularWord() and any helper function(s) to the answer box!
Test code 1:
const int WORDS_SIZE = 5;
string words[WORDS_SIZE] = {"hello", "world", "hello", "world", "hello"};Test code 2:
const int WORDS_SIZE = 5;
string words[WORDS_SIZE] = {"apple", "corn", "corn", "apple", "lettuce"};Explanation: The last word that appeared with a frequency of 2 is “apple” at index 3. Therefore, based on our rules, that is the word that will be displayed instead of “corn”.
Fitness Statistics
Bob recently started a daily fitness routine to improve his overall health. Every day, he tracks the number of steps he takes, and after a few weeks of consistent effort, he now wants to analyze his data to gain some insights into his progress.
To help him, Bob needs two(2) functions written in C++ that will allow him to understand his fitness journey better.
Function 1: Bob is curious about how his total step count has increased over time. This function will calculate the cumulative sum of his daily step count, showing him the total distance he’s covered since he started tracking.
void stepCountCumulativeSum( int daily_steps[],
const int NUM_DAYS,
int cumulative_steps[] )
{
// ...
}| Function: | stepCountCumulativeSum( int[], const int, int[]) |
| Purpose: | Calculates the cumulative sum of the daily step counts and records the running total in the cumulative_steps array. The cumulative sum represents the total number of steps Bob has taken up to each respective day, providing a running total of his overall progress. The function should not print anything. |
| Parameters: | int daily_steps[]: array of Bob’s daily step count. const int NUM_DAYS: Size of daily_steps array and cumulative_steps arrayint cumulative_steps[]: Array to be filled with Bob’s cumulative step count. |
| Return value: | The function doesn’t return any value. |
Example:
// Assume the proper libraries are included
// Assume the proper implementation of stepCountCumulativeSum() is included
int main()
{
const int NUM_DAYS = 5;
int daily_steps[NUM_DAYS] = {5000, 4000, 5000, 2000, 4000};
int cumulative_steps[NUM_DAYS];
stepCountCumulativeSum(daily_steps, NUM_DAYS, cumulative_steps);
// We are printing the contents of the cumulative_steps array here.
return 0;
}
// OUTPUT
// 5000
// 9000
// 14000
// 16000
// 20000const int NUM_DAYS = 3;
int daily_steps[NUM_DAYS] = {10000, 2000, 6000};
int cumulative_steps[NUM_DAYS];Test code 2:
const int NUM_DAYS = 4;
int daily_steps[NUM_DAYS] = {4000, 2000, 8000, 3000};
int cumulative_steps[NUM_DAYS];
Function 2: Bob is also interested in how consistent he has been with his daily steps. This function will calculate the mean of his daily step count and return the deviation, showing him which days he was above or below his regular activity level.
double stepCountDeviation( int daily_steps[ ],
const int NUM_DAYS,
const int OPTIMAL_STEP_COUNT )
{
// ...
}| Function: | stepCountDeviation( int[], const int, const int ) |
| Purpose: | Calculates the mean of daily step counts and returns the deviation deviation = mean - optimal step count The function should not print anything. |
| Parameters: | int daily_steps[]: array of Bob’s daily step count. const int NUM_DAYS: Size of daily_steps array const int OPTIMAL_STEP_COUNT: Desired step count per day. |
| Return value: | The function will return a double, which is the calculated deviation |
Example:
// Assume the proper libraries are included
// Assume the proper implementation of stepCountDeviation() is included
int main()
{
const int NUM_DAYS = 5;
int daily_steps[NUM_DAYS] = {5000, 4000, 5000, 2000, 4000};
const int OPTIMAL_STEP_COUNT = 5000;
double deviation = stepCountDeviation(daily_steps, NUM_DAYS, OPTIMAL_STEP_COUNT);
// We are printing the deviation up to 3 decimal places
cout << fixed << setprecision(3) << deviation << endl;
return 0;
}
// OUTPUT:
// -1000.000Explanation:
mean= (5000 + 4000 + 5000 + 2000 + 4000)/5 = 4000deviation=mean-OPTIMAL_STEP_COUNT= 4000 - 5000 = -1000
For Question 2, develop and validate your solution in VS Code. Once you are happy with your solution, go to coderunner on Canvas and paste stepCountCumulativeSum(), stepCountDeviation(), and any helper function(s) to the answer box!
Test code 1:
const int NUM_DAYS = 3;
int daily_steps[NUM_DAYS] = {10000, 2000, 6000};
const int OPTIMAL_STEP_COUNT = 5000;Test code 2:
const int NUM_DAYS = 4;
int daily_steps[NUM_DAYS] = {4000, 2000, 8000, 3000};
const int OPTIMAL_STEP_COUNT = 750;
Normal Heart Rate
As a pediatrician, you need to monitor newborns’ heart rates, which should fall between 70 and 190 bpm. To simplify this task, write a function printNormalHeartRates() that takes two arrays: one with patient names and another with their heart rates. The function will print the names of patients with normal heart rates.
void printNormalHeartRates(string patients[],
int heart_rate[],
const int NUM_PATIENTS)
{
// ...
}| Function: | printNormalHeartRates (string, int, int) |
| Purpose: | Prints out the patients with normal heart rates. Where normal heart rate is between 70 and 190, both inclusive. You may assume that both patients[] and heart_rate[] arrays will be the same size. |
| Parameters: | string patients[]: Array of strings which contains the patient’s names. int heart_rate[]: Array of int which contains their heart rate const int NUM_PATIENTS: An integer that gives the number of elements in the patient and heart rate arrays |
| Return value: | - The function doesn’t return any value. - Your function should print out all patients whose heart rate is within the range |
| Error handling/ Boundary conditions: | - You may assume that the patients[] array and heart_rate[] array are non-empty - You may also assume that the size of the patients[] array and heart_rate[] array are always equal |
Example:
// Assume the proper libraries are included
// Assume the proper implementation of printNormalHeartRates() is included
int main()
{
string patients[3] = {"Jamie", "Sebastien", "Shaun"};
int heart_rate[3] = {90, 70, -12};
printNormalHeartRates(patients, heart_rate, 3);
return 0;
}
// OUTPUT
// Jamie 90
// Sebastien 70For Question 3, develop and validate your solution in VS Code. Once you are happy with your solution, go to coderunner on Canvas and paste printNormalHeartRates() and any helper function(s) to the answer box!
Test code 1:
string patients[4] = {"Joe", "Jack", "Amy", "Bob"};
int heart_rate[4] = {70, 80, 190, 100};
printNormalHeartRates(patients, heart_rate, 4);Test code 2:
string patients[6] = {"Chloe Kim", "Rene Rinnekangas", "Shaun White", "A", "B", "C"};
int heart_rate[6] = {190, 70, 191, 69, 71, 189};
printNormalHeartRates(patients, heart_rate, 6);
Best Time to Buy and Sell a House
Flipping is a real estate strategy that involves buying homes and selling them for a profit in a short period of time. You want to maximize your profit by choosing a single day to buy a house and choosing a different day in the future to sell that house.
int maxProfit( int prices[], const int NUM_MONTHS )
{
// ...
}| Function: | maxProfit(int[], const int) |
| Purpose: | Find the maximum profit achieved from buying and selling a house. The function should not print anything. |
| Parameters: | int prices[]: Array of prices of the house every month const int NUM_MONTHS: The size of prices array |
| Return value: | It should return the maximum profit achieved through one house flip. |
| Error handling/Boundary conditions: | - Return 0 if no profit can be achieved. - You may assume that the prices[] array is always non-empty |
Example:
// Assume the proper libraries are included
// Assume the proper implementation of maxProfit() is included
int main()
{
const int NUM_MONTHS = 6;
int prices[NUM_MONTHS] = {700000, 100000, 500000, 300000, 600000, 400000};
int profit = maxProfit(prices, NUM_MONTHS);
cout << "Maximum profit: " << profit << endl;
return 0;
}
// OUTPUT
// Maximum Profit: 500000Explanation:
- Buy on month 2 (price = 100000) and sell on month 5 (price = 600000)
- profit = 600000-100000 = 500000.
- Note: Buying on month 2 and selling on month 1 is not allowed because you must buy before you sell.
For Question 4, develop and validate your solution in VS Code. Once you are happy with your solution, go to coderunner on Canvas and paste maxProfit() and any helper function(s) to the answer box!
Test code 1:
const int NUM_MONTHS = 5;
int prices[NUM_MONTHS] = {700000, 600000, 400000, 300000, 100000};Explanation: In this case, no profitable transactions are possible, and the max profit = 0.
Test code 2:
const int NUM_MONTHS = 6;
int prices[NUM_MONTHS] = {700000, 300000, 400000, 100000, 400000, 100000};Explanation: Buy on month 4 (price = 100000) and sell on month 5 (price = 400000), profit = 400000-100000 = 300000.
Splitting a String
HINT: use stringstream.
PROTIP: compile using -Wsign-compare e.g. if saved to file named foo.cpp, use
g++ -Wall -Werror -Wpedantic -Wsign-compare foo.cpp
When you’re processing data, it’s useful to break up a text string into pieces using a delimiter. Write a function split() that takes a string, splits it at every occurrence of a delimiter, and then populates an array of strings with the split pieces, up to the provided maximum number of pieces.
int split( string input_string,
char separator,
string arr[],
const int ARR_SIZE )
{
// ...
}
| Function: | split( string, char, string[], const int ) |
| Purpose: | Break a text string into pieces using the given delimiter and populate each piece in the array. The function does not print anything. |
| Parameters: | string input_string: The text string containing data separated by a delimiter char separator: The delimiter marking the location where the string should be split up string arr[]: The array that will be used to store the input text string’s individual string pieces const int ARR_SIZE: The number of elements that can be stored in the array |
| Return value: | - The function returns an int, the number of pieces the input text string is split into. - Populate arr[] with the all the element. |
| Error Handling/ Boundary Conditions: | - Return 1 if the delimiter character is not found. Place the entire string in the array as the first element - Return -1 if the string is split into more pieces than the size of the array. Fill the array with as many pieces of the split string as possible. - Return 0 if an empty string is provided. |
Example:
// Assume the proper libraries are included
// Assume the proper implementation of split() is included
void printArray(string arr[], const int NUM_ELEMENTS)
{
for (int i=0; i < NUM_ELEMENTS; i++)
{
cout << "arr["<< i << "]:" << arr[i] << endl;
}
}
int main()
{
string input_string = "ABCDEFG";
char separator = ' ';
const int ARR_SIZE = 3;
string arr[ARR_SIZE];
// num_splits is the value returned by split
int num_splits = split(input_string, separator, arr, ARR_SIZE);
cout << "Function returned value: " << num_splits << endl;
if(num_splits != -1)
{
printArray(arr, num_splits);
}
else
{
printArray(arr, ARR_SIZE);
}
}
// OUTPUT:
// Function returned value: 1
// arr[0]:ABCDEFGFor Question 5, develop and validate your solution in VS Code. Once you are happy with your solution, go to coderunner on Canvas and paste split() and any helper function(s) to the answer box!
Test code 1:
string testcase = "RST,UVW,XYZ";
char separator = ',';
const int ARR_SIZE = 3;
string arr[ARR_SIZE];
// num_splits is the value returned by split
int num_splits = split(testcase, separator, arr, ARR_SIZE);
cout << "Function returned value: " << num_splits << endl;
for (int i=0; i < ARR_SIZE; i++){
cout << "arr["<< i << "]:" << arr[i] << endl;
}Test code 2:
string testcase = "Bangkok,Berlin,Birmingham,Bogota,Busan,Baton Rouge,Beaumont,Boise,Budapest";
char separator = ',';
const int ARR_SIZE = 5;
string arr[ARR_SIZE];
// num_splits is the value returned by split
int num_splits = split(testcase, separator, arr, ARR_SIZE);
cout << "Function returned value: " << num_splits << endl;
for (int i=0; i < ARR_SIZE; i++){
cout << "arr["<< i << "]:" << arr[i] << endl;
}Explanation:The string can be split into more pieces than the size of the array; thus, we returned -1 and filled the array with as many pieces as possible.
School Exam Scores
You’re helping your teacher analyze student exam scores across 10 subjects. Each row represents a student’s scores in these subjects. Your task is to identify the first student whose average score falls below a defined threshold. Write a function minAverg that returns the index of the first student with an average score below the threshold.
int minAverg( int scores[][10],
const int NUM_STUDENTS,
double threshold )
{
// ...
}
| Function: | minAverg( int, int, double ) |
| Purpose: | A function to return the index of a student whose average score is less than or equal to the threshold. |
| Parameters: | int scores[][10]: A 2D integer array with 10 columns for storing the scores for each of the 10 subjects const int NUM_STUDENTS: An integer number of rows for each student double threshold: A floating number threshold for low average score. |
| Return value: | The function returns an int representing the index of the first student with a low average score that is less than or equal to the threshold. |
| Error handling/Boundary conditions: | - The function returns -1 if there is no average score that is less than or equal to the threshold - You may assume that the score[][] array is non-empty |
Example:
// Assume the proper libraries are included
// Assume the proper implementation of minAverg() is included
int main()
{
int scores[2][10] = {
{80, 90, 85, 95, 88, 82, 75, 89, 91, 87},
{1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
};
cout << "returned student index: " << minAverg(scores, 2, 10.0);
return 0;
}
// OUTPUT:
// returned student index: 1For Question 6, develop and validate your solution in VS Code. Once you are happy with your solution, go to coderunner on Canvas and paste minAverg() and any helper function(s) to the answer box!
Test code 1:
int scores[3][10] = {
{10, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{2, 2, 2, 2, 2, 2, 2, 2, 2, 20},
{3, 3, 3, 3, 3, 30, 3, 3, 3, 3}
};
cout << "returned student index: " << minAverg(scores, 2, 25);Test code 2:
int scores[4][10] = {
{50, 60, 55, 65, 70, 60, 58, 62, 55, 65},
{70, 80, 75, 85, 90, 65, 78, 82, 88, 74},
{10, 20, 15, 25, 12, 30, 18, 22, 17, 15},
{100, 110, 105, 115, 120, 90, 108, 102, 114, 104},
};
cout << "returned student index: " << minAverg(scores, 5, 40);Test code 3:
int scores[5][10] = {
{ 1, 1, 1, 1, 1, 1, 1, 1, 1, 1 },
{ 1, 1, 1, 1, 1, 1, 1, 1, 1, 1 },
{ 1, 1, 10, 1, 1, 1, 1, 1, 1, 1 },
{ 1, 1, 1, 1, 1, 1, 1, 1, 1, 1 },
{ 1, 1, 1, 1, 1, 1, 1, 1, 1, 1 }
};
cout << "returned student index: " << minAverg(scores, 5, 9);